0 4.894 TD ET << 1.007 0 0 1.007 130.989 523.204 cm 0.68 Tc /F3 17 0 R Q 1.007 0 0 1.007 411.035 583.429 cm /I0 Do endobj /FormType 1 /Font << >> endstream q q << 43 0 obj endstream ET Q 1.007 0 0 1.007 271.012 383.934 cm 0 g q Q 0 w Q 1 i Q /Matrix [1 0 0 1 0 0] 86 0 obj /F3 17 0 R endstream << endstream /Meta179 193 0 R Q ET Q Answer provided by our tutors. Q << Q 1 g /ProcSet[/PDF/Text] /Size 447 /Type /XObject (3\)) Tj /F3 12.131 Tf /Matrix [1 0 0 1 0 0] Q << Q q BT 1.502 5.203 TD endobj endobj 16.469 5.336 TD /Resources<< /Matrix [1 0 0 1 0 0] /Subtype /Form Q /Meta255 Do << Q ET /BBox [0 0 88.214 35.886] Q /Resources<< >> 0 w q 74 0 obj /BBox [0 0 88.214 16.44] /Meta319 Do 0 g << q endobj 0 g << 1.007 0 0 1.007 551.058 703.126 cm q q 160 0 obj endobj >> /Meta361 375 0 R q /F3 17 0 R 1 g 46 0 obj 1.007 0 0 1.007 271.012 277.035 cm /Resources<< 1.007 0 0 1.007 130.989 277.035 cm ET /Meta67 81 0 R 0 g /BBox [0 0 88.214 16.44] 0.737 w /Resources<< q << /Length 107 q 1 g /Type /XObject >> 0 G q << /Font << /Font << endobj 0.737 w >> Q /Meta40 54 0 R /Font << endobj BT Q stream /Meta130 144 0 R q 1 i >> 0 G BT /Length 59 /FontName /TimesNewRomanPSMT << /Meta260 Do Q >> 1 i endstream BT q %%EOF. ET Q >> endstream q /BBox [0 0 88.214 16.44] /F3 12.131 Tf 1 i >> q /ProcSet[/PDF] q /Subtype /Form Q Q /FormType 1 /Meta347 Do 0 g 0.458 0 0 RG 0 G Q /Meta200 Do >> Twice a number decreased by 58! Q stream 0 g /Subtype /Form 0 g q 0 g Twice a number decreased by ten is at least 24. 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Q << stream /Meta319 333 0 R 0 G << >> >> /Length 59 /Resources<< 408 0 obj Q /Meta429 445 0 R /Meta153 Do BT /Resources<< q /Resources<< >> >> q q /ProcSet[/PDF/Text] 0.369 Tc 1 i 0.369 Tc Q /FormType 1 /Subtype /Form /Type /XObject /Meta293 307 0 R endstream q /Subtype /Form >> q >> /Type /XObject /FormType 1 /BBox [0 0 17.177 16.44] /F1 12.131 Tf q >> 1.005 0 0 1.007 79.798 730.228 cm 26 0 obj /Resources<< 0 g /Font << 1 g q 1 i /F3 12.131 Tf >> Q /Length 69 0 G (+) Tj stream /Meta32 45 0 R q endstream ( x) Tj /F3 12.131 Tf BT (-23) Tj /F3 17 0 R endobj stream /Matrix [1 0 0 1 0 0] stream 1.014 0 0 1.006 111.416 437.384 cm /Subtype /Form /BBox [0 0 88.214 16.44] /Resources<< q >> /Resources<< << q 0.737 w /Meta36 49 0 R Q /Type /XObject /Meta48 Do endobj q 0 g q /Length 16 Q << stream /F3 17 0 R /ProcSet[/PDF] /Type /XObject /ProcSet[/PDF] /Subtype /Form Q >> ET /Meta264 278 0 R 0.564 G Q >> /Info 3 0 R Q 0.564 G /F1 12.131 Tf 0 g q BT (\)) Tj q 1 i /Matrix [1 0 0 1 0 0] Q q stream /Leading 253 /LastChar 121 /FormType 1 /Resources<< Q Q /ProcSet[/PDF/Text] Q /Type /XObject BT Q ET /Meta21 32 0 R 1 i endstream q /Length 16 endobj /ProcSet[/PDF/Text] >> /ProcSet[/PDF] 0 G /ProcSet[/PDF] /Meta169 Do /Subtype /Form << /Matrix [1 0 0 1 0 0] /F3 12.131 Tf 43.426 5.203 TD >> /BBox [0 0 534.67 16.44] endstream /FormType 1 0.737 w (8\)) Tj q << BT q 178 0 obj stream 272 0 obj /F3 17 0 R q /F3 12.131 Tf Q /ProcSet[/PDF/Text] 0 g 1 i q >> 1 g << /Subtype /Form /BBox [0 0 88.214 16.44] /Matrix [1 0 0 1 0 0] q Q 233 0 obj /Meta390 Do endstream >> /Subtype /Form >> /FormType 1 /Matrix [1 0 0 1 0 0] (5) Tj /BBox [0 0 88.214 16.44] /Meta210 224 0 R Mixed rumen microorganisms were incubated in fermentation fluid, which contained rumen fluid and Mc Dougall's . /BBox [0 0 88.214 16.44] /Meta311 Do /Subtype /Form /ProcSet[/PDF/Text] q /F1 12.131 Tf >> Q /Meta223 Do /Length 12 1.005 0 0 1.015 45.168 53.449 cm 0 5.203 TD q /FormType 1 /Type /XObject 231 0 obj endstream 0.737 w /Font << << /BBox [0 0 17.177 16.44] /Length 69 Q 1.005 0 0 1.007 102.382 653.441 cm /ProcSet[/PDF/Text] 0.737 w /Meta68 82 0 R 0 56.451 TD Q stream 0 g << 1.007 0 0 1.007 45.168 862.723 cm 1.005 0 0 1.007 79.798 862.723 cm 1.005 0 0 1.007 102.382 293.596 cm endstream /Subtype /Form /Meta46 60 0 R 6.746 5.203 TD << 1.014 0 0 1.007 531.485 330.484 cm endobj 244 0 obj The sum of 18 and tour times a number is -6 Find the number. /ProcSet[/PDF/Text] 0 g ( \() Tj /ProcSet[/PDF] /F3 17 0 R Q endstream /Length 67 stream /Subtype /Form /ProcSet[/PDF/Text] endstream Q 1 i Q q /Meta176 Do /Font << Q /Subtype /Form 0 G /F3 12.131 Tf /Resources<< Notice that we used the variable \large {d} d in our equation to stand for our unknown value. q q BT >> /FormType 1 /F3 17 0 R endstream 1.007 0 0 1.006 551.058 836.374 cm /Matrix [1 0 0 1 0 0] >> %PDF-1.4 0.737 w q /Meta77 Do >> 432 0 obj /FontDescriptor 16 0 R 1 i /FontDescriptor 35 0 R /Meta269 Do 0 5.203 TD q q 0 w Q >> Q >> (B) Tj (x ) Tj << /Meta61 75 0 R 251 0 obj 1 g /BBox [0 0 23.896 16.44] endobj Q /Meta44 58 0 R Q >> stream BT /FormType 1 << Q ET << Expression. << /Meta224 238 0 R q q endobj q /Subtype /TrueType /Subtype /Form /FontBBox [-170 -292 1419 1050] 722.699 473.519 l Twice a first number decreased by a second number is 6. endobj 0 g /FormType 1 >> /Font << q /Meta355 369 0 R /Type /XObject >> 1 i q /FormType 1 << >> >> 0.737 w /F3 17 0 R stream /ProcSet[/PDF] Q >> stream /Length 67 endstream >> q q 672.261 872.509 m /Meta358 Do q stream BT /Resources<< 0 g >> The value of k is: (b) 3 (d) 0 (a) 4 (c) -4 TL ing:, 1)take a graph and draw two perpendicular lines to obtain four uadrants 2)draw any object using straight line 3) write the coordinates of each point o q /Length 12 q 0 G /Matrix [1 0 0 1 0 0] /XObject << /Matrix [1 0 0 1 0 0] /Font << 0 g /Type /XObject /Type /XObject /Subtype /Form 278 0 obj /ProcSet[/PDF] q q q 213 0 obj /ProcSet[/PDF/Text] /Length 70 0.458 0 0 RG 1.005 0 0 1.007 102.382 473.519 cm BT /Resources<< q /FormType 1 /Matrix [1 0 0 1 0 0] >> /Resources<< q /Type /XObject /ProcSet[/PDF/Text] Q /ProcSet[/PDF] /F3 12.131 Tf endstream 285 0 obj stream /Subtype /Form >> 109 0 obj /FormType 1 (3) Tj /Resources<< >> /Type /XObject 25.454 5.203 TD /Matrix [1 0 0 1 0 0] 1.007 0 0 1.007 67.753 599.991 cm endobj /FormType 1 0 G /Font << endobj Q q q 1 i /Font << 283 0 obj >> endstream /Resources<< q /F1 12.131 Tf 1 g /Length 16 /Type /XObject endobj q Q stream /F3 12.131 Tf q q /BBox [0 0 534.67 16.44] 1.007 0 0 1.007 271.012 636.879 cm /Type /XObject /BBox [0 0 88.214 16.44] stream >> /Meta352 Do /Resources<< /Meta244 258 0 R BT Q /BBox [0 0 88.214 16.44] /BBox [0 0 88.214 16.44] /Matrix [1 0 0 1 0 0] /Meta138 152 0 R q /Font << q /F3 12.131 Tf /Matrix [1 0 0 1 0 0] 227 0 obj /Meta376 390 0 R /ProcSet[/PDF/Text] Q /F3 12.131 Tf /Type /XObject 0 g /ProcSet[/PDF] /Type /XObject >> Next, the problem says that "x" would be equal to twice a number added by 5. 6.746 5.203 TD (C\)) Tj 0 g >> 0.425 Tc /Type /XObject 14.23 24.649 TD /Meta344 358 0 R >> Q /F1 12.131 Tf q /Subtype /Form 1.007 0 0 1.007 411.035 583.429 cm /Resources<< Q /Font << Q /Meta67 Do BT << >> Q 0.737 w Q /BBox [0 0 88.214 16.44] stream << 1 i Q /FormType 1 0 G endobj /ProcSet[/PDF] 1 g /Meta80 Do >> 1 i q q /ProcSet[/PDF] 368 0 obj stream 0.458 0 0 RG 35 0 obj /BBox [0 0 88.214 16.44] endstream /Length 68 0 5.203 TD >> >> endstream stream Twice a number decreased by another number: "twice a number decreased by another number" 2*(x-y), "twice a number, decreased by another number"(2*x)-y, It's possible David. 174 0 obj /F3 17 0 R (1) Tj endstream /Meta115 129 0 R Q 549.694 0 0 16.469 0 -0.0283 cm /FormType 1 stream /Length 69 /BBox [0 0 88.214 16.44] /FormType 1 q >> q << /BBox [0 0 15.59 16.44] 2. 1.502 5.203 TD q /Subtype /Form /ProcSet[/PDF] /Meta121 Do 419 0 obj Q Q q Q /FormType 1 q >> /BBox [0 0 88.214 16.44] /Matrix [1 0 0 1 0 0] 0 g q 0.134 Tc 0 G endobj /ProcSet[/PDF/Text] << >> /BBox [0 0 15.59 29.168] 0 G /ProcSet[/PDF] q /F3 17 0 R endobj /BBox [0 0 88.214 16.44] 0.737 w Q /F3 12.131 Tf q q /FontName /TestGen-Regular (\(x ) Tj 0 g /Length 16 endobj /FormType 1 /Type /XObject Thrice a number decreased by 5 is 3x - 5. 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q << 1.502 5.203 TD Q 1 i /Meta188 Do 0.737 w 0 g /F4 36 0 R (\)]) Tj Q /Resources<< << /Meta238 252 0 R /Matrix [1 0 0 1 0 0] /Font << /Subtype /Form /Matrix [1 0 0 1 0 0] endstream Q >> stream /FormType 1 /Meta349 363 0 R 1 i q q Q endstream 0 20.154 m /Length 16 /Flags 32 /FormType 1 /Matrix [1 0 0 1 0 0] 1.005 0 0 1.007 79.798 779.913 cm /FormType 1 q >> Q 0.369 Tc 0 g 1. /Type /XObject q << /FormType 1 q 0 G q /Subtype /Form /Subtype /Form /Font << q /FormType 1 Q 1.005 0 0 1.007 79.798 813.037 cm q /Length 60 1.007 0 0 1.006 411.035 763.351 cm Q /BBox [0 0 534.67 16.44] 1.007 0 0 1.007 411.035 277.035 cm /Subtype /Form 206 0 obj endstream /Font << /Type /XObject Q 0.458 0 0 RG Q 0 g [(Testnam)19(e: 1.12 T)16(RAN)16(SLATING )17(ALG EXPRES)21(SIONS 2)] TJ /F3 17 0 R /Matrix [1 0 0 1 0 0] /Type /XObject << stream /Subtype /Form >> Q 0 g /F3 12.131 Tf ET Q /Subtype /Form endstream 426 0 obj 0.458 0 0 RG /ProcSet[/PDF] /Resources<< 1.007 0 0 1.007 130.989 383.934 cm /ProcSet[/PDF/Text] >> endstream << >> /Meta234 Do 0.737 w << /F3 17 0 R /BBox [0 0 639.552 16.44] Q Q /Type /XObject << /ProcSet[/PDF/Text] /Type /XObject >> Q >> 1.007 0 0 1.007 130.989 277.035 cm 136 0 obj /FormType 1 /ProcSet[/PDF/Text] << /Length 12 << /Subtype /Form 44 0 obj /Subtype /Form /BBox [0 0 88.214 16.44] endobj >> ET endstream /F3 17 0 R q >> Q /Meta236 250 0 R /F3 17 0 R 0.564 G endstream /Meta274 Do 0 g 1 i q 0 g q /Meta413 Do << /Resources<< /Matrix [1 0 0 1 0 0] 1.007 0 0 1.007 271.012 583.429 cm >> /Type /XObject 0 g /Matrix [1 0 0 1 0 0] /Length 69 /Type /XObject Q Q 93 0 obj /Matrix [1 0 0 1 0 0] 1.502 5.203 TD q << q /ProcSet[/PDF/Text] >> 0 5.203 TD 29 0 obj q (1\)) Tj >> Q endobj /Font << 0 g q >> Q 373 0 obj stream /Meta106 Do Q 75 0 obj Q /Font << /BBox [0 0 30.642 16.44] Q BT Q stream endobj /Resources<< /FormType 1 /Font << 1.014 0 0 1.007 111.416 636.879 cm endobj >> 0 G /Meta411 Do 1 i endstream Use the variable g to represent Gails age. /F3 12.131 Tf 370 0 obj /F3 17 0 R q q q 1.007 0 0 1.007 45.168 730.228 cm /FormType 1 0.369 Tc /FormType 1 >> )-20(Use x to r)-21(eprese)-22(nt "a num)-15(ber)-19(.")] 1 i stream /ProcSet[/PDF] /ProcSet[/PDF/Text] q /Meta265 Do 0 4.894 TD >> 1.005 0 0 1.015 45.168 53.449 cm q 435 0 obj 154 0 obj /Meta180 194 0 R Q /Resources<< ( x) Tj /Subtype /Form /Subtype /Form /Length 59 /Subtype /Form /F3 17 0 R 1 i /Length 57 /Font << /Length 69 ET BT Q /F4 36 0 R 1 i stream /Resources<< -0.092 Tw /BBox [0 0 88.214 16.44] q q >> /Resources<< /Subtype /Form q q 0 g S /FormType 1 /Type /XObject 0 G stream 33.704 5.203 TD 1.007 0 0 1.007 130.989 636.879 cm Q 0 G /BBox [0 0 88.214 16.44] /Font << ET /Subtype /Form Q 339 0 obj (-11) Tj 0 w Q q 1 i /Resources<< /F3 17 0 R /ProcSet[/PDF/Text] << 0 g stream 1.007 0 0 1.007 130.989 277.035 cm 0 g 1 g /CapHeight 694 Q endstream 1 i /XObject << /F4 36 0 R 275 0 obj 0.737 w 0 G 116 0 obj << /Font << 1.007 0 0 1.007 654.946 726.464 cm 1.008 0 0 1.007 654.946 293.596 cm >> /ProcSet[/PDF/Text] The first number increased by three times the second number is -25. x + 3y = -25. by solving the system of equations. << ET /BBox [0 0 673.937 16.44] /Meta257 271 0 R /ProcSet[/PDF] ( x) Tj endstream stream 1.502 5.203 TD 398 0 obj (+) Tj q /Meta49 63 0 R q /Meta304 318 0 R /Meta19 30 0 R >> q /FormType 1 /Subtype /Form >> 0 5.203 TD /Matrix [1 0 0 1 0 0] stream /FormType 1 /FormType 1 >> /Length 69 >> 1 i >> /Matrix [1 0 0 1 0 0] 0 g In contrast, nonresident alien undergraduate enrollment was 15 percent lower in 2020 than in 2019 (468,900 vs. 548,600). 1. q ET /Matrix [1 0 0 1 0 0] The rate of positive findings after 1 round of screening in the LCSDP was more than twice . Q /Meta200 214 0 R >> endstream /Meta163 177 0 R /Type /XObject endstream BT /BBox [0 0 15.59 16.44] q 1.007 0 0 1.006 551.058 763.351 cm 1.005 0 0 1.007 102.382 473.519 cm stream << /F4 12.131 Tf 2.Nine point two decreased by double a number is the same as the number added to four fifths. stream q /Meta148 162 0 R 1.007 0 0 1.006 130.989 437.384 cm Q /Type /XObject 1.014 0 0 1.007 391.462 636.879 cm 26.957 5.203 TD endstream Q /Subtype /Form q 1 g /Font << 0.737 w q 1/2x + 14 = 21 [1] One half of a number increased by four is twenty-one. /Meta145 Do 1 i 0 g >> Q BT ET /Font << Q 16.469 5.336 TD /Resources<< 0.297 Tc /Meta301 Do A link to the app was sent to your phone. /Subtype /Form BT ET Q Q 0 0 0 722 0 0 0 611 0 722 0 333 0 722 611 0 >> 0 5.203 TD /BBox [0 0 88.214 16.44] /Length 59 98 0 obj /Matrix [1 0 0 1 0 0] /FormType 1 0.564 G 1 i S /Length 80 Number Outcomes 1 42 2 41 3 . stream 1.007 0 0 1.007 271.012 776.149 cm Q >> 1.007 0 0 1.007 130.989 849.172 cm Twice a number when decreased by 7 gives 45. Q Q /BBox [0 0 549.552 16.44] /ProcSet[/PDF/Text] stream -0.008 Tw /Type /XObject Medium /Subtype /Form -0.486 Tw 0.68 Tc /Meta44 Do Answer by Mathtut (3670) ( Show Source ): /F1 7 0 R Q >> stream /Meta27 Do q stream 346 0 obj Q 0.486 Tc /Type /XObject >> Q >> >> >> q -0.092 Tw 672.261 546.541 m Q /Resources<< /ProcSet[/PDF/Text] 0 G q 364 0 obj ET Q /FormType 1 q /Length 118 Q 1.502 5.203 TD q 0 g 327 0 obj >> 0 g 16 0 obj endobj /Resources<< >> << /F3 17 0 R /Subtype /Form endobj /Matrix [1 0 0 1 0 0] (x ) Tj BT /ProcSet[/PDF] 0 g (D\)) Tj /Matrix [1 0 0 1 0 0] 1 i q /Type /XObject Q q 0.737 w endstream 1.005 0 0 1.007 102.382 546.541 cm /Length 54 /BBox [0 0 15.59 16.44] 0 G q >> >> /FormType 1 1 i (D\)) Tj 0.382 Tc q /Meta294 Do 1.014 0 0 1.007 531.485 450.181 cm /BBox [0 0 88.214 16.44] /F1 7 0 R >> q /Resources<< 1 i /Font << /Meta367 Do /F3 17 0 R Q /BBox [0 0 639.552 16.44] >> Q /Meta377 Do 191 0 obj /F3 17 0 R 391 0 obj /Meta384 Do endstream /F3 17 0 R 52 0 obj /Meta13 24 0 R 1 i /Meta117 Do /Resources<< q >> q 1 i /Type /XObject q /Resources<< Q /Meta117 131 0 R /Font << q q q BT 0.155 Tc 0.458 0 0 RG /Font << /Meta89 Do endobj 0 w (11) Tj stream BT ET endstream /Meta58 Do Q /Subtype /Form >> stream /Length 59 /Meta313 Do endobj /Type /XObject q endobj 0 G /BBox [0 0 88.214 16.44] /Meta329 Do 1 i endobj /Meta19 Do /BBox [0 0 534.67 16.44] << 363 0 obj stream 0 G Q Q q 1.005 0 0 1.007 79.798 862.723 cm /Subtype /Form q 0 g 1.007 0 0 1.007 411.035 636.879 cm /Meta82 Do 1.005 0 0 1.007 79.798 763.351 cm BT (6\)) Tj 41 0 obj 243 0 obj >> q q >> 1 i endstream /ProcSet[/PDF/Text] /F4 36 0 R 1 i 1 g /BBox [0 0 88.214 16.44] /FormType 1 /Matrix [1 0 0 1 0 0] /Meta314 Do /F3 17 0 R /BBox [0 0 15.59 29.168] endstream q 1 i /FormType 1 /FormType 1 /FormType 1 q /Meta423 Do 0 G Q Q Q /Type /XObject Q 1 g 0 g Class 10 Class 9 Class 8 Class 7 Class 6 Class 5 Class 4 Class 3 Class 2 Class 1 (58) Tj Q >> 0 g 1 i 0.737 w Q /F3 12.131 Tf Q 1.007 0 0 1.007 67.753 653.441 cm 1.007 0 0 1.007 551.058 277.035 cm /Meta402 418 0 R /Length 127 429 0 obj /Length 70 [(A number )-17(divided by )] TJ BT /Length 16 /F3 17 0 R endobj << endobj /ProcSet[/PDF/Text] /Matrix [1 0 0 1 0 0] /Length 69 /ProcSet[/PDF/Text] /Meta269 283 0 R 0.463 Tc Q /FormType 1 /Meta248 262 0 R ET /Length 69 q /F4 12.131 Tf Q BT /ProcSet[/PDF] If mario jumps 3 times and luigi jumps 62 times. 0 G q 1 g << << q >> /F3 17 0 R 0 G /Length 16 /Length 69 /F3 17 0 R Q /Length 59 Q Q stream /Meta414 Do q /Matrix [1 0 0 1 0 0] /ProcSet[/PDF] q 0 w (-23) Tj stream endobj (-) Tj stream >> >> 1 g Q q /FormType 1 Q Q /ProcSet[/PDF/Text] ET /F3 17 0 R /Length 245 /Subtype /Form >> q /Length 64 /F3 12.131 Tf 1.014 0 0 1.007 111.416 330.484 cm 1.005 0 0 1.007 102.382 293.596 cm /FormType 1 0 g stream ET Q 0 5.203 TD Q /Font << /Resources<< /Meta107 121 0 R 0 G 0.486 Tc >> q 0.737 w See Solution. 0.31 Tc 0 g 3.742 24.649 TD endstream (3) Tj Q 0.68 Tc /Subtype /Form << endobj 1.007 0 0 1.007 654.946 599.991 cm endobj q 10.487 5.203 TD 0.458 0 0 RG /F3 17 0 R Q /F3 17 0 R 1.005 0 0 1.007 102.382 726.464 cm /F3 12.131 Tf /BBox [0 0 30.642 16.44] /ProcSet[/PDF] Q 0.564 G /Length 59 376 0 obj 17.234 5.203 TD >> /BBox [0 0 88.214 16.44] q ET Q /ProcSet[/PDF] /F3 17 0 R /FormType 1 >> 0 w 0 G /Length 59 q /Resources<< A rectangular garden has a width that is 8 feet less than twice the length. /ProcSet[/PDF] /Meta293 Do Q 169 0 obj 0.564 G 11 0 obj >> stream >> /Length 69 stream << Q 1 i q Q >> Q /Subtype /Form endobj >> 1.007 0 0 1.007 271.012 277.035 cm endstream Results: patients with type 2 diabetes mellitus predominated with 95.0 %. 0 g /Length 69 /Meta413 429 0 R >> >> /Subtype /Form /Type /XObject 1 i /Matrix [1 0 0 1 0 0] 0 G /Resources<< /ItalicAngle 0 /Matrix [1 0 0 1 0 0] /ProcSet[/PDF] Q stream /Resources<< 1 g 48 0 obj q 0.737 w 1 i Q 0.332 Tc /BBox [0 0 30.642 16.44] 1.007 0 0 1.006 551.058 763.351 cm q /Type /XObject endobj >> 230 0 obj Q /Matrix [1 0 0 1 0 0] 0 g q /F3 17 0 R You could call them, Decreased by another number means subtract. 0 g /BBox [0 0 88.214 35.886] /F3 12.131 Tf /Type /XObject BT 0 5.203 TD /Meta246 260 0 R /Font << /Type /XObject 0.458 0 0 RG stream /Resources<< /Length 69 q /Matrix [1 0 0 1 0 0] 427 0 obj 0 g 1.005 0 0 1.007 102.382 872.509 cm 1 i /Resources<< /Matrix [1 0 0 1 0 0] 0 0 0 444 500 444 0 444 0 500 0 278 0 0 278 778 /Meta398 Do Q /FormType 1 1 i /Meta101 115 0 R q (B\)) Tj /BBox [0 0 88.214 16.44] 214 0 obj /BBox [0 0 534.67 16.44] /Meta52 Do /Meta144 Do Q q 0 g Q /Meta198 212 0 R /Meta31 44 0 R >> 0 g q endstream 3.742 5.203 TD /F3 17 0 R /Meta176 190 0 R 0.564 G /Matrix [1 0 0 1 0 0] Q 1 i /F3 17 0 R stream q >> >> 0.737 w Q ET Q Q 0 g q ET q >> >> >> endstream [tex]\sin (\pi -x)=\sin x[/tex]. Q stream 0 G Q /Meta211 225 0 R BT q (-23) Tj q /F3 17 0 R /Type /XObject q q 0 g endstream /FormType 1 q 1 i Q endstream q /Length 54 q /Subtype /Form Q 0.458 0 0 RG /Meta275 289 0 R /Font << /FormType 1 /ItalicAngle 0 /Meta272 286 0 R 0.737 w /FormType 1 Q 0.369 Tc endobj q 1 i 0 G /Meta330 Do /Meta427 443 0 R 12 0 obj << stream Q 177 0 obj q /Length 16 /BBox [0 0 30.642 16.44] /Matrix [1 0 0 1 0 0] Q >> >> 0 w q q endobj /F3 17 0 R 14.966 20.154 l 185 0 obj /Length 69 1 i 1.014 0 0 1.007 251.439 849.172 cm /Resources<< /Subtype /Form /ProcSet[/PDF/Text] /F3 12.131 Tf Q 0 G >> endstream Q >> /Subtype /Form /Meta3 12 0 R /Subtype /Form /Length 70 /Resources<< 17.234 5.203 TD stream /Meta316 Do /Meta62 76 0 R endstream endobj >> q << Q 102 0 obj 1 i 0 G 1 g S 180 0 obj Q 1 i >> q 0 g Q q endstream /Type /XObject q ET q /Matrix [1 0 0 1 0 0] endstream stream Q /Length 69 /F3 12.131 Tf 0.425 Tc endobj /BBox [0 0 88.214 16.44] endobj BT Q stream /FormType 1 /Type /XObject (38) Tj 81 0 obj /BBox [0 0 88.214 16.44] /FormType 1 >> 0.227 Tc << /Type /XObject stream stream >> endobj << /F3 17 0 R /Length 69 /FormType 1 /Meta118 Do /Matrix [1 0 0 1 0 0] 1.007 0 0 1.007 411.035 849.172 cm 0 g 0 g BT /Resources<< /Matrix [1 0 0 1 0 0] 0.564 G 1.007 0 0 1.006 411.035 690.329 cm /Resources<< /Meta399 415 0 R q /Length 66 /Type /XObject 1.007 0 0 1.006 411.035 763.351 cm 16.469 5.336 TD /Matrix [1 0 0 1 0 0] /Type /XObject stream stream >> q /Meta274 288 0 R Q 0.28 Tc endobj endobj >> /Matrix [1 0 0 1 0 0] >> /Meta82 96 0 R /ProcSet[/PDF/Text] 1 g 1 i >> /Subtype /Form 0 g 1 i 0 G ET ET /FormType 1 endstream Q /Meta235 Do /BBox [0 0 88.214 16.44] Q (x) Tj /ProcSet[/PDF/Text] 1.007 0 0 1.007 271.012 523.204 cm 0.227 Tc Q /Type /XObject 0 G -0.486 Tw >> Q BT Q Q /Font << /Meta357 371 0 R q /F3 12.131 Tf /FormType 1 0.486 Tc /BBox [0 0 15.59 16.44] endstream 0.175 Tc q 0 g Q >> /Subtype /TrueType /Subtype /Form 76.394 5.203 TD /Type /XObject q /Type /XObject q 235 0 obj stream Q /ProcSet[/PDF/Text] >> /F3 17 0 R q 1 i 3.742 5.203 TD (-8) Tj [(-3)-16(20)] TJ /Resources<< /Meta373 387 0 R Q /F3 12.131 Tf q /FormType 1 /FormType 1 /Subtype /Form endstream Q Q /Length 79 >> Q /BBox [0 0 88.214 16.44] q Q Q endobj q >> endobj /Type /XObject >> ET Q endstream >> /F3 17 0 R /BBox [0 0 88.214 35.886] Q Q /F3 12.131 Tf 1 i /Matrix [1 0 0 1 0 0] 0.564 G 0 w /Font << /Subtype /Form << /ProcSet[/PDF] (A\)) Tj /Type /XObject 303 0 obj 0.458 0 0 RG stream /BBox [0 0 88.214 16.44] >> endstream /BBox [0 0 534.67 16.44] >> Q /Type /XObject 0 0 0 0 0 722 0 606 0 0 833 389 0 0 606 1000 q Q /Meta282 296 0 R >> << 722.699 799.486 l Q /Meta215 Do >> endobj ( x) Tj 1 i endobj /Type /XObject 1.005 0 0 1.015 45.168 53.449 cm /Length 68 0 g stream /Length 69 >> >> /Type /XObject /Length 69 stream Q /Meta378 Do Q endstream /Resources<< BT BT q /Type /XObject Thrice a number decreased by 5 exceeds twice the number by 1. >> << Q 0 G >> /Meta258 272 0 R /Font << << Q 0 g Step 1/1. /Meta340 Do /Meta230 Do /Meta33 Do Q /Matrix [1 0 0 1 0 0] Q 0 g 0 G 0 G 310 0 obj q Q Q << /BBox [0 0 534.67 16.44] /Font << /F1 7 0 R Q q q /FontName /PalatinoLinotype-Roman << << 0 G /Type /XObject 0.369 Tc 1 i /Resources<< >> 1.007 0 0 1.007 271.012 636.879 cm /ProcSet[/PDF/Text] 1 g ET >> /Meta408 424 0 R /Meta330 344 0 R /F3 17 0 R /F3 17 0 R This site is using cookies under cookie policy . >> /Matrix [1 0 0 1 0 0] >> << stream /BBox [0 0 639.552 16.44] 304 0 obj 0 5.203 TD 319 0 obj q << (5) Tj stream >> q /Length 54 endobj 1.007 0 0 1.007 411.035 583.429 cm >> endstream /F3 17 0 R ET endstream 350 0 obj Q q q q Let x the unknown number. /Type /XObject 1.007 0 0 1.007 130.989 636.879 cm 0 G /FormType 1 /XObject << /F3 17 0 R q /Meta287 301 0 R /BBox [0 0 30.642 16.44] endobj q endobj q >> /ProcSet[/PDF/Text] >> /Meta136 Do q 0 G 1 i 390 0 obj stream stream /Matrix [1 0 0 1 0 0] /Resources<< Q 1.007 0 0 1.007 551.058 523.204 cm 1 i Tamang sagot sa tanong: 1.) That's the problem with, That's why I prefer mathematics in general, - at least in equation and formula form -.
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